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UGC-NET | UGC-NET CS 2017 Dec 2 | Question 5

Last Updated : 12 Mar, 2018
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The Octal equivalent of the binary number 1011101011 is :
(A) 7353
(B) 1353
(C) 5651
(D) 5657


Answer: (B)

Explanation:

Quiz of this Question
Please comment below if you find anything wrong in the above post


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