8086 program to print the table of input integer

Problem – Write an assembly language program in 8086 to print the table of input integer. 

Assumption – Suppose the inputted number is at memory location 500 and the table will be printed from starting location 600 till 609 in hexadecimal. 

Example – 

Algorithm – 

1. Load input number address in SI and also load the address where we want output in DI . 
    
2. Store 00 in CH register. 
    
3. Increment value of CH by 1 and move the content of [SI] into AH register. 
    
4. Multiply content of AL and CH and store it in AX and then move content of AL into [DI], then increment value of DI by 1. 
    
5. Compare the value of CH and 0A, if not equal then go to step number 3 otherwise halt the program. 
    

Program – 

Explanation – 

1. MOV SI, 500: load 500 in SI. 
    
2. MOV DI, 600: load 600 in DI. 
    
3. MOV CH, 00: load 00 data in CH register. 
    
4. INC CH: increment the value inside CH register by 1. 
    
5. MOV AL, SI: move the content of SI into AL register. 
    
6. MUL CH: multiply the contents of AL and CH register and store in AX register. 
    
7. MOV [DI], AL: move the contents of AL register into [DI]. 
    
8. INC DI: increment the value of DI by 1. 
    
9. CMP CH, 0A: subtract data inside CH register and 0A. 
    
10. JNZ 408: jump to address 408 if zero flag is 0. 
     
11. HLT: terminate the program.