BigInteger testBit() Method in Java
Last Updated :
04 Dec, 2018
prerequisite : BigInteger Basics
The java.math.BigInteger.testBit(index) method returns true if and only if the designated bit is set. This method Computes (this & (1<<n)) != 0).
Syntax:
public boolean testBit(int n)
Parameter: The method takes one parameter n of integer type which refers to the index of the bit that needs to be tested.
Return Value: The method returns true if and only if the designated bit is set else it will return false.
Exception: The method will throw an ArithmeticException when n is negative.
Examples:
Input: BigInteger = 2300, n = 4
Output: true
Explanation:
Binary Representation of 2300 = 100011111100
bit at index 4 is 1 so set it means bit is set
so method will return true
Input: BigInteger = 5482549 , n = 1
Output: false
Below program illustrates the testBit() method of BigInteger.
import java.math.*;
public class GFG {
public static void main(String[] args)
{
BigInteger biginteger = new BigInteger( "2300" );
int i = 3 ;
boolean flag = biginteger.testBit(i);
String result = "The bit at index " + i + " of " +
biginteger + " is set = " + flag;
System.out.println(result);
}
}
|
Output:
The bit at index 3 of 2300 is set = true
Reference: https://docs.oracle.com/javase/7/docs/api/java/math/BigInteger.html#testBit(int)
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