Class 11 NCERT Solutions- Chapter 5 Complex Numbers And Quadratic Equations – Exercise 5.1 | Set 2 Last Updated : 05 Apr, 2021 Improve Improve Like Article Like Save Share Report Chapter 5 Complex Numbers And Quadratic Equations – Exercise 5.1 | Set 1For Q.11 to Q.13 find the multiplicative inverse of the given number Question 11. 4-3i Solution: Let’s denote given number as a, the complement of a = = = (4+3i) Modulus of a = (|a|) = √((4)2+(3)2) |a|= √(16+9)=√(25) |a| = 5 = = Question 12. √5+3i Solution: Let’s denote given number as a, the complement of a = = √5-3i Modulus of a (|a|) = √((√5)2+(-3)2) |a|= √(5+9)=√(14) |a|=√(14) Question 13. -i Solution: Let’s denote given number as a, the complement of a = = i Modulus of a (|a|) = √((0)2+(-1)2) |a|= √(1) |a|=1 = i Express the following expression in form of a+ibQuestion 14. Solution: Let’s denote the given expression as z, z = z = z = As we know that (a+b)(a-b) = a2 – b2 z = z = z = z = z = As we can write = -i z = z = 0- Like Article Suggest improvement Previous Class 11 NCERT Solutions- Chapter 5 Complex Numbers And Quadratic Equations - Exercise 5.1 | Set 1 Next Class 11 NCERT Solutions- Chapter 5 Complex Numbers And Quadratic Equations - Exercise 5.2 Share your thoughts in the comments Add Your Comment Please Login to comment...