Class 11 RD Sharma Solutions – Chapter 29 Limits – Exercise 29.10 | Set 2 Last Updated : 04 May, 2021 Improve Improve Like Article Like Save Share Report Evaluate the following limits:Question 16. Solution: We have, = = = Asand, we get, = = 2 Question 17. Solution: We have, = = = Asand, we get, = log e × 1 = 1 Question 18. Solution: We have, = = = = = Asand, we get, = 1 − = Question 19. Solution: We have, = = = Let h = x/a − 1. We get, = We know,. So, we have, = = Question 20. Solution: We have, = = = = = = We know,. So, we have, = = Question 21. Solution: We have, = = = = We know,. So, we have, = Question 22. Solution: We have, = = = = We know,. So, we have, = Question 23. Solution: We have, = = = = = = We know,. So, we have, = = Question 24. Solution: We have, = = = = As, we get, = log 8 − log 2 = = log 4 Question 25. Solution: We have, = = = Asand, we get, = (log 2) × 2 = 2 log 2 = log 4 Question 26. Solution: We have, = = = = = = We know,. So, we have, = = Question 27. Solution: We have, = = = = We know,and. So, we get, = 1 Question 28. Solution: We have, = = We know,. So, we have, = = a0 × log a = log a Question 29. Solution: We have, = = = = = As numerator and denominator are both zero for x = 0, therefore limit cannot exist. Question 30. Solution: We have, = Let x = h + 5. We get, = = = We know,. So, we have, = e5 × log e = e5 Like Article Suggest improvement Previous Class 11 RD Sharma Solutions - Chapter 29 Limits - Exercise 29.10 | Set 1 Next Class 11 RD Sharma Solutions - Chapter 29 Limits - Exercise 29.11 Share your thoughts in the comments Add Your Comment Please Login to comment...