C++ Program to Print array after it is right rotated K times
Given an Array of size N and a values K, around which we need to right rotate the array. How to quickly print the right rotated array?
Examples :Â
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Input: Array[] = {1, 3, 5, 7, 9}, K = 2.
Output: 7 9 1 3 5
Explanation:
After 1st rotation - {9, 1, 3, 5, 7}
After 2nd rotation - {7, 9, 1, 3, 5}
Input: Array[] = {1, 2, 3, 4, 5}, K = 4.
Output: 2 3 4 5 1
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Approach:
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- We will first take mod of K by N (K = K % N) because after every N rotations array will become the same as the initial array.Â
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- Now, we will iterate the array from i = 0 to i = N-1 and check,Â
- If i < K, Print rightmost Kth element (a[N + i -K]). Otherwise,Â
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- Print array after ‘K’ elements (a[i – K]).Â
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Below is the implementation of the above approach.Â
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C++
#include<bits/stdc++.h>
using namespace std;
void RightRotate( int a[], int n, int k)
{
k = k % n;
for ( int i = 0; i < n; i++)
{
if (i < k)
{
cout << a[n + i - k] << " " ;
}
else
{
cout << (a[i - k]) << " " ;
}
}
cout << "
";
}
int main()
{
int Array[] = { 1, 2, 3, 4, 5 };
int N = sizeof (Array) / sizeof (Array[0]);
int K = 2;
RightRotate(Array, N, K);
}
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Time complexity : O(n)Â
Auxiliary Space : O(1)
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Please refer complete article on Print array after it is right rotated K times for more details!
Last Updated :
25 Jan, 2022
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