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C++ Program to Print matrix in snake pattern

Last Updated : 12 Aug, 2022
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Given an n x n matrix in the given matrix, you have to print the elements of the matrix in the snake pattern.

Examples: 

Input :mat[][] = { {10, 20, 30, 40},
                   {15, 25, 35, 45},
                   {27, 29, 37, 48},
                   {32, 33, 39, 50}};
              
Output : 10 20 30 40 45 35 25 15 27 29
         37 48 50 39 33 32 

Input :mat[][] = { {1, 2, 3},
                   {4, 5, 6},
                   {7, 8, 9}};
Output : 1 2 3 6 5 4 7 8 9

Matrix printing

We traverse all rows. For every row, we check if it is even or odd. If even, we print from left to right else print from right to left. 

C++




// C++ program to print matrix in snake order
#include <iostream>
#define M 4
#define N 4
using namespace std;
 
void print(int mat[M][N])
{
    // Traverse through all rows
    for (int i = 0; i < M; i++) {
 
        // If current row is even, print from
        // left to right
        if (i % 2 == 0) {
            for (int j = 0; j < N; j++)
                cout << mat[i][j] << " ";
 
        // If current row is odd, print from
        // right to left
        } else {
            for (int j = N - 1; j >= 0; j--)
                cout << mat[i][j] << " ";
        }
    }
}
 
// Driver code
int main()
{
    int mat[][] = { { 10, 20, 30, 40 },
                    { 15, 25, 35, 45 },
                    { 27, 29, 37, 48 },
                    { 32, 33, 39, 50 } };
 
    print(mat);
    return 0;
}


Output : 

10 20 30 40 45 35 25 15 27 29 37 48 50 39 33 32 

Time complexity: O(N^2) for given N*N matrix

Auxiliary Space: O(1)

Please refer complete article on Print matrix in snake pattern for more details!



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