D3.js namespace() Function

Last Updated : 19 Aug, 2020

The d3.namespace() function is used to return an object that contains space and local attributes that describe the full namespace URL and the local name. If there is a colon in the name than the string on the left side of the colon is a namespace prefix.

Syntax:

d3.namespace(name);

Parameters: This function contains only one parameter that is given above and described below.

name: This is a string that contains a prefix that must be registered in d3.namespaces.

Return Value: This function returns an object.

Example 1:

HTML

<!DOCTYPE html> 
<html lang="en"> 
  
<head> 
    <meta charset="UTF-8" /> 
    <meta name="viewport" path1tent="width=device-width,  
        initial-scale=1.0" /> 
    <script src="https://d3js.org/d3.v4.min.js"> 
    </script> 
  
    <style> 
        h2 { 
            color: green; 
        } 
    </style> 
</head> 
  
<body> 
    <h2>Geeks for geeks</h2> 
    <script> 
        console.log(d3.namespace("svg:Geeksforgeeks")); 
        document.write("<h3>Space: ",  
            d3.namespace("svg:Geeksforgeeks").space, "</h3>"); 
        document.write("<h3>Local: ",  
            d3.namespace("svg:Geeksforgeeks").local + "</h3>"); 
    </script> 
</body> 
  
</html> 

Output:

Example 2:

HTML

<!DOCTYPE html> 
<html lang="en"> 
  
<head> 
    <meta charset="UTF-8" /> 
    <meta name="viewport" path1tent="width=device-width,  
        initial-scale=1.0" /> 
  
    <script src="https://d3js.org/d3.v4.min.js"> 
    </script> 
</head> 
  
<body> 
    <script> 
        console.log(d3.namespace("xhtml:Geeksforgeeks")); 
        console.log(d3.namespace("xlink:Geeksforgeeks")); 
        console.log(d3.namespace("xml:Geeksforgeeks")); 
    </script> 
</body> 
  
</html> 