Finding Natural Logarithm of Given Number in Golang
Last Updated :
01 Apr, 2020
Go language provides inbuilt support for basic constants and mathematical functions to perform operations on the numbers with the help of the math package. You are allowed to find the natural logarithm of the specified number with the help of Log() function provided by the math package. So, you need to add a math package in your program with the help of the import keyword to access Log() function.
Syntax:
func Log(a float64) float64
- If you pass +Inf in this function, then this function will return +Inf.
- If you pass 0 in this function, then this function will return -Inf.
- If the value of a<0, then this function will return NaN.
- If you pass NaN in this function, then this function will return NaN.
Example 1:
package main
import (
"fmt"
"math"
)
func main() {
res_1 := math.Log(0)
res_2 := math.Log(1)
res_3 := math.Log(math.Inf(1))
res_4 := math.Log(math.NaN())
res_5 := math.Log(6)
fmt.Printf( "Result 1: %.1f" , res_1)
fmt.Printf( "\nResult 2: %.1f" , res_2)
fmt.Printf( "\nResult 3: %.1f" , res_3)
fmt.Printf( "\nResult 4: %.1f" , res_4)
fmt.Printf( "\nResult 5: %.1f" , res_5)
}
|
Output:
Result 1: -Inf
Result 2: 0.0
Result 3: +Inf
Result 4: NaN
Result 5: 1.8
Example 2:
package main
import (
"fmt"
"math"
)
func main() {
nvalue_1 := math.Log(4)
nvalue_2 := math.Log(8)
res := nvalue_1 + nvalue_2
fmt.Printf( "%.5f + %.5f = %.5f" ,
nvalue_1, nvalue_2, res)
}
|
Output:
1.38629 + 2.07944 = 3.46574
Like Article
Suggest improvement
Share your thoughts in the comments
Please Login to comment...