Finding the Inverse Tangent of Complex Number in Golang
Last Updated :
27 Mar, 2020
Go language provides inbuilt support for basic constants and mathematical functions for complex numbers with the help of the cmplx package. You are allowed to find the inverse tangent of the specified complex number with the help of the Atan() function provided by the math/cmplx package. So, you need to add a math/cmplx package in your program with the help of the import keyword to access the Atan() function.
Syntax:
func Atan(x complex128) complex128
Let us discuss this concept with the help of the given examples:
Example 1:
package main
import (
"fmt"
"math/cmplx"
)
func main() {
res_1 := cmplx.Atan(3 + 5i)
res_2 := cmplx.Atan(-4 + 8i)
res_3 := cmplx.Atan(-8 - 7i)
fmt.Println( "Result 1:" , res_1)
fmt.Println( "Result 2:" , res_2)
fmt.Println( "Result 3:" , res_3)
}
|
Output:
Result 1: (1.4808695768986575+0.14694666622552977i)
Result 2: (-1.5203354344612496+0.10008092715193644i)
Result 3: (-1.4998477994928145-0.06171501948288145i)
Example 2:
package main
import (
"fmt"
"math/cmplx"
)
func main() {
cnumber_1 := complex(5, 7)
cnumber_2 := complex(6, 9)
cvalue_1 := cmplx.Atan(cnumber_1)
cvalue_2 := cmplx.Atan(cnumber_2)
res := cvalue_1 + cvalue_2
fmt.Println( "Complex Number 1: " , cnumber_1)
fmt.Println( "Inverse tangent 1: " , cvalue_1)
fmt.Println( "Complex Number 2: " , cnumber_2)
fmt.Println( "Inverse tangent 2: " , cvalue_2)
fmt.Println( "Final sum: " , res)
}
|
Output:
Complex Number 1: (5+7i)
Inverse tangent 1: (1.502726846368326+0.09444062638970716i)
Complex Number 2: (6+9i)
Inverse tangent 2: (1.5192555225335465+0.07687117493699018i)
Final sum: (3.0219823689018726+0.17131180132669732i)
Like Article
Suggest improvement
Share your thoughts in the comments
Please Login to comment...