Assume every process requires 3 seconds of service time in a system with single processor. If new processes are arriving at the rate of 10 processes per minute, then estimate the fraction of time CPU is busy in system?
(A) 20%
(B) 30%
(C) 50%
(D) 60%
Answer: (C)
Explanation:
10 processes -> 1 min
1 process-> 1/10 min = 6 sec (Arrival rate)
Each process -> 3 sec service time 3/6 * 100 = 50% of time CPU is busy.
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