How to find largest of three numbers using JavaScript ?
To find the largest of three numbers using JavaScript, we have multiple approaches. In this article, we are going to learn how to find the largest of three numbers using JavaScript.
Below are the approaches to finding the largest of three numbers using JavaScript:
This is a straightforward approach using if-else statements to compare the numbers and find the largest one.
Example: In this example, we are using a Conditional Statement(if-else).
Javascript
function findLargest(num1, num2, num3) {
if (num1 >= num2 && num1 >= num3) {
return num1;
} else if (num2 >= num1 && num2 >= num3) {
return num2;
} else {
return num3;
}
}
const largestNumber = findLargest(10, 5, 8);
console.log( "Largest number:" , largestNumber);
|
Output
Largest number: 10
Approach 2: Using the Math.max() Method
The Math.max()
method can be used to find the maximum of a list of numbers.
Example: In this example, we are using Math.max() Method.
Javascript
function findLargest(num1, num2, num3) {
return Math.max(num1, num2, num3);
}
const largestNumber = findLargest(10, 5, 8);
console.log( "Largest number:" , largestNumber);
|
Output
Largest number: 10
Spread the numbers in an array using the spread operator and then use Math.max()
.
Example: In this example, we are using Spread Operator with Math.max().
Javascript
function findLargest(num1, num2, num3) {
return Math.max(...[num1, num2, num3]);
}
const largestNumber = findLargest(10, 5, 8);
console.log( "Largest number:" , largestNumber);
|
Output
Largest number: 10
The ternary operator can be used to concisely express the comparison.
Example: In this example, we are using Ternary Operator.
Javascript
function findLargest(num1, num2, num3) {
return num1 >= num2 && num1 >= num3 ? num1
: num2 >= num1 && num2 >= num3 ? num2
: num3;
}
const largestNumber = findLargest(10, 5, 8);
console.log( "Largest number:" , largestNumber);
|
Output
Largest number: 10
Put the numbers in an array and use Array.sort()
to sort them in ascending order. The largest number will be at the end of the array.
Example: In this example, we are using Array.sort().
Javascript
function findLargest(num1, num2, num3) {
const numbers = [num1, num2, num3];
numbers.sort((a, b) => a - b);
return numbers[numbers.length - 1];
}
const largestNumber = findLargest(10, 5, 8);
console.log( "Largest number:" , largestNumber);
|
Output
Largest number: 10
Last Updated :
03 Jan, 2024
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