How to Get Uint32 Type Random Number in Golang?
Last Updated :
26 Mar, 2020
Go language provides inbuilt support for generating random numbers of the specified type with the help of a math/rand package. This package implements pseudo-random number generators. These random numbers are generated by a source and this source produces a deterministic sequence of values every time when the program run. And if you want to random numbers for security-sensitive work, then use the crypto/rand package.
You are allowed to generate a pseudo-random number of a 32-bit integer as an uint32 type from the default source with the help of the Uint32() function provided by the math/rand package. So, you need to add a math/rand package in your program with the help of the import keyword to access the Uint32() function.
Syntax:
func Uint32() uint32
Let us discuss this concept with the help of the given examples:
Example 1:
package main
import (
"fmt"
"math/rand"
)
func main() {
res_1 := rand.Uint32()
res_2 := rand.Uint32()
res_3 := rand.Uint32()
fmt.Println("Random Number 1: ", res_1)
fmt.Println("Random Number 2: ", res_2)
fmt.Println("Random Number 3: ", res_3)
}
|
Output:
Random Number 1: 2596996162
Random Number 2: 4039455774
Random Number 3: 2854263694
Example 2:
package main
import (
"fmt"
"math/rand"
)
func uint32random(value_1, value_2 uint32) uint32 {
return value_1 + value_2 + rand.Uint32()
}
func main() {
res1 := uint32random(10, 3)
res2 := uint32random(44, 59)
res3 := uint32random(130, 50)
fmt.Println("Result 1: ", res1)
fmt.Println("Result 2: ", res2)
fmt.Println("Result 3: ", res3)
}
|
Output:
Result 1: 2596996175
Result 2: 4039455877
Result 3: 2854263874
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