ISRO | ISRO CS 2016 | Question 5
The minimum Boolean expression for the following circuit is:
(A) AB + AC + BC
(B) A + BC
(C) A + B
(D) A + B + C
Answer: (A)
Explanation: We need to consider the different paths through which current can flow in this circuit by making the circuit complete.
These 3 paths exist and the expression will be:
A(B+C) + AB + (A+B)C
= AB + AC + AB + AC + BC
= AB + AC + BC.
So, option (A) is correct.
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Last Updated :
22 Mar, 2018
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