- cosh() : java.lang.Math.cosh() method returns the hyperbolic cosine of the argument passed.
Special cases :
- Result is NaN, if argument is NaN.
- Result is 1.0, if the argument is zero.
- Result is +ve infinity, if argument is infinite.
Syntax:
public static double cosh(double arg)
Parameters:
arg - The number whose hyperbolic cosine is to be returned.
Returns:
the hyperbolic cosine of the argument arg.
- decrementExact() : java.lang.Math.decrementExact() method decrements the value of passed argument by one.
Syntax:
public static int decrementExact(int arg)
or
public static long decrementExact(long arg)
Parameters:
arg - argument passed.
Returns:
return argument decremented by one.
Throws:
Exception if the result overflows long or int datatype, according to the
argumented data type.
- exp() : java.lang.Math.exp(double arg) method returns the Euler’s number raised to the power of double argument.
Important cases:
- Result is NaN, if argument is NaN.
- Result is +ve infinity, if the argument is +ve infinity.
- Result is +ve zero, if argument is -ve infinity.
Syntax:
public static double exp(double arg)
Parameters:
arg - argument passed.
Returns:
Euler’s number raised to the power of passed argument
Java code explaining exp(), decrementExact(), cosh() method in lang.Math class.
import java.math.*;
public class NewClass
{
public static void main(String[] args)
{
double value = 2;
double coshValue = Math.cosh(value);
System.out.println("Hyperbolic Cosine of " + coshValue);
System.out.println("");
int result = Math.decrementExact(3051);
System.out.println("Use of decrementExact() : " + result);
System.out.println("");
double exponent = 34;
double expVal = Math.exp(exponent);
System.out.println("Value of exp : "+ expVal);
}
}
|
Output:
Using addExact() : 9
acos value of Asini : NaN
acos value of Asinj : 0.054858647341251204
cube root : 6.0
- incrementExact() : java.lang.Math.incrementExact() method returns the argument by incrementing it’s value.
Syntax:
public static int incrementExact(int arg)
or
public static long incrementExact(long arg)
Parameters:
arg - the argument
Returns:
incremented value of the argument
- log10() : java.lang.Math.log10() method returns the base10 logarithmic value of the passed argument.
Syntax:
public static double log(double arg)
Parameters:
arg - argument passed.
Returns:
base10 logarithmic value of the argument passed.
- pow() : java.lang.Math.pow(double b, double e) method returns the value as be
Syntax:
public static double pow(double b,double e)
Parameters:
b : base
e : exponent
Returns:
value as baseexponent
JAVA code explaining incrementExact(), log10(), pow() method in lang.Math class.
import java.lang.*;
public class NewClass
{
public static void main(String[] args)
{
int f1 = 30, f2 = -56;
f1 =Math.incrementExact(f1);
System.out.println("Incremented value of f1 : "+f1);
f2 =Math.incrementExact(f2);
System.out.println("Incremented value of f2 : "+f2);
System.out.println("");
double value = 10;
double logValue = Math.log10(value);
System.out.println("Log10 value of 10 : "+logValue);
System.out.println("");
double b = 10, e = 2;
double power = Math.pow(b,e);
System.out.println("Use of pow() : "+power);
}
}
|
Output :
Incremented value of f1 : 31
Incremented value of f2 : -55
Log10 value of 10 : 1.0
Use of pow() : 100.0
- signum() : java.lang.Math.signum() method returns the signum value of the argument passed.
-1 if x < 0
signum fun(x) = 0 if x = 0
1 if x > 0
Note: Result is NaN, if passed the argument is NaN.;
Syntax:
public static double signum(double x)
or
public static float signum(float x)
Parameters:
x - the argument whose signum value we need
Returns:
signum value of x
- round() : java.lang.Math.round() method round off the passed argument upto closest decimal places.
Note: Result is 0, if the argument is NaN.
Syntax:
public static long round(long arg)
or
public static double round(double arg)
Parameters:
arg - argument needs to round off
Returns:
round off value of the argument
- max() : java.lang.Math.max(double v1, double v2) method returns the greater value out of the two passed argument values.
This method just compares using magnitude without considering any sign.
Syntax:
public static double max(double v1, double v2)
Parameters:
v1 - first value
v2 - second value
Returns:
v1 or v2 based on which number is greater.
It can return either of the two if v1 = v2.
Java code explaining signum(), round(), max() method in lang.Math class.
import java.lang.*;
public class NewClass
{
public static void main(String args[])
{
double x = 10.4556, y = -23.34789;
double signm = Math.signum(x);
System.out.println("Signum of 10.45 = "+signm);
signm = Math.signum(y);
System.out.println("Signum of -23.34 = "+signm);
System.out.println("");
double r1 = Math.round(x);
System.out.println("Round off 10.4556 = "+r1);
double r2 = Math.round(y);
System.out.println("Round off 23.34789 = "+r2);
System.out.println("");
double m = Math.max(r1, r2);
System.out.println("Max b/w r1 and r2 = "+r2);
}
}
|
Output:
Signum of 10.45 = 1.0
Signum of -23.34 = -1.0
Round off 10.4556 = 10.0
Round off 23.34789 = -23.0
Max b/w r1 and r2 = -23.0
- log1p() : java.lang.Math.log1p() method returns natural log of (passed argument + 1).
Syntax:
public static double log1p(double arg)
Parameters:
arg - the argument
Returns:
log of (argument + 1).
This result is within 1 unit in the last place of exact result.
- ulp() : java.lang.Math.ulp() method returns Unit of least precision(ulp) ie. the least distance between two floating point numbers.
Here, it is the least distance b/w the argument and next larger value.
Syntax:
public static double ulp(double arg)
or
public static float ulp(float arg)
Parameters:
arg - argument passed.
Returns:
least distance b/w the argument and next larger value.
Java code explaining ulp(), log1p() method in lang.Math class.
import java.lang.*;
public class NewClass
{
public static void main(String args[])
{
double x = 34.652, y = -23.34789;
double u = Math.ulp(x);
System.out.println("ulp of 34.652 : "+u);
u = Math.ulp(y);
System.out.println("ulp of -23.34789 : "+u);
System.out.println("");
double l = 99;
double l1 = Math.log1p(l);
System.out.println("Log of (1 + 99) : "+l1);
l1 = Math.log(100);
System.out.println("Log of 100 : "+l1);
}
}
|
Output:
ulp of 34.652 : 7.105427357601002E-15
ulp of -23.34789 : 3.552713678800501E-15
Log of (1 + 99) : 4.605170185988092
Log of 100 : 4.605170185988092
.
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