Java Program For Recursive Selection Sort For Singly Linked List – Swapping Node Links
Last Updated :
30 Mar, 2022
Given a singly linked list containing n nodes. The problem is to sort the list using the recursive selection sort technique. The approach should be such that it involves swapping node links instead of swapping node data.
Examples:
Input: 10 -> 12 -> 8 -> 4 -> 6
Output: 4 -> 6 -> 8 -> 10 -> 12
In Selection Sort, we first find the minimum element, swap it with the beginning node and recur for the remaining list. Below is the recursive implementation of these steps for the linked list.
recurSelectionSort(head)
if head->next == NULL
return head
Initialize min = head
Initialize beforeMin = NULL
Initialize ptr = head
while ptr->next != NULL
if min->data > ptr->next->data
min = ptr->next
beforeMin = ptr
ptr = ptr->next
if min != head
swapNodes(&head, head, min, beforeMin)
head->next = recurSelectionSort(head->next)
return head
swapNodes(head_ref, currX, currY, prevY)
head_ref = currY
prevY->next = currX
Initialize temp = currY->next
currY->next = currX->next
currX->next = temp
The swapNodes(head_ref, currX, currY, prevY) is based on the approach discussed here but it has been modified accordingly for the implementation of this post.
Java
class GFG{
static class Node
{
int data;
Node next;
};
static Node swapNodes(Node head_ref,
Node currX,
Node currY,
Node prevY)
{
head_ref = currY;
prevY.next = currX;
Node temp = currY.next;
currY.next = currX.next;
currX.next = temp;
return head_ref;
}
static Node recurSelectionSort(Node head)
{
if (head.next == null )
return head;
Node min = head;
Node beforeMin = null ;
Node ptr;
for (ptr = head; ptr.next != null ;
ptr = ptr.next)
{
if (ptr.next.data < min.data)
{
min = ptr.next;
beforeMin = ptr;
}
}
if (min != head)
head = swapNodes(head, head,
min, beforeMin);
head.next =
recurSelectionSort(head.next);
return head;
}
static Node sort(Node head_ref)
{
if ((head_ref) == null )
return null ;
head_ref = recurSelectionSort(head_ref);
return head_ref;
}
static Node push(Node head_ref,
int new_data)
{
Node new_node = new Node();
new_node.data = new_data;
new_node.next = (head_ref);
(head_ref) = new_node;
return head_ref;
}
static void printList( Node head)
{
while (head != null )
{
System.out.print(head.data + " " );
head = head.next;
}
}
public static void main(String args[])
{
Node head = null ;
head = push(head, 6 );
head = push(head, 4 );
head = push(head, 8 );
head = push(head, 12 );
head = push(head, 10 );
System.out.println(
"Linked list before sorting:" );
printList(head);
head = sort(head);
System.out.print(
"Linked list after sorting:" );
printList(head);
}
}
|
Output:
Linked list before sorting:
10 12 8 4 6
Linked list after sorting:
4 6 8 10 12
Time Complexity: O(n2)
Auxiliary Space: O(n)
Please refer complete article on Recursive selection sort for singly linked list | Swapping node links for more details!
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