Lex program to check whether a given number is even or odd
Last Updated :
30 Apr, 2019
Given a number n, the task is to check whether the given n is even or odd using Lex program.
Examples:
Input : 10
Output : Even
Input : 5
Output : Odd
Prerequisite: FLEX (Fast Lexical Analyzer Generator)
An even number is an integer which is “evenly divisible” by 2. This means that if the integer is divided by 2, it yields no remainder or 0 as remainder. Similarly, an Odd number is an integer which is not “evenly divisible” by 2 and will leaves 1 as remainder.
Below is the implementation of above approach:
%{
#include<stdio.h>
int i;
%}
%%
[0-9]+ {i= atoi (yytext);
if (i%2==0)
printf ( "Even" );
else
printf ( "Odd" );}
%%
int yywrap(){}
int main()
{
yylex();
return 0;
}
|
Output:
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