Matcher group() method in Java with Examples
Last Updated :
26 Nov, 2018
The group() method of Matcher Class is used to get the input subsequence matched by the previous match result.
Syntax:
public String group()
Parameters: This method do not takes any parameter.
Return Value: This method returns the String which is the input subsequence matched by the previous match.
Exception: This method throws IllegalStateException if no match has yet been attempted, or if the previous match operation failed.
Below examples illustrate the Matcher.group() method:
Example 1:
import java.util.regex.*;
public class GFG {
public static void main(String[] args)
{
String regex = "(G*s)";
Pattern pattern
= Pattern.compile(regex);
String stringToBeMatched
= "GeeksForGeeks";
Matcher matcher
= pattern
.matcher(stringToBeMatched);
MatchResult result
= matcher.toMatchResult();
System.out.println("Current Matcher: "
+ result);
while (matcher.find()) {
System.out.println(matcher.group());
}
}
}
|
Output:
Current Matcher: java.util.regex.Matcher[pattern=(G*s) region=0, 13 lastmatch=]
s
s
Example 2:
import java.util.regex.*;
public class GFG {
public static void main(String[] args)
{
String regex = "(G*G)";
Pattern pattern
= Pattern.compile(regex);
String stringToBeMatched
= "GFG FGF GFG";
Matcher matcher
= pattern
.matcher(stringToBeMatched);
MatchResult result
= matcher.toMatchResult();
System.out.println("Current Matcher: "
+ result);
while (matcher.find()) {
System.out.println(matcher.group());
}
}
}
|
Output:
Current Matcher: java.util.regex.Matcher[pattern=(G*G) region=0, 11 lastmatch=]
G
G
G
G
G
Reference: Oracle Doc
Like Article
Suggest improvement
Share your thoughts in the comments
Please Login to comment...