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Number of Reflexive Relations on a Set

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Given a number n, find out the number of Reflexive Relation on a set of first n natural numbers {1, 2, ..n}.

Examples : 

Input: n = 2
Output: 4
The given set A = {1, 2}. The following are reflexive relations on A * A :
{{1, 1), (2, 2)}
{(1, 1), (2, 2), (1, 2)}
{(1, 1), (2, 2), (1, 2), (2, 1)}
{(1, 1), (2, 2), (2, 1)}

Input: n = 3
Output: 64

Explanation :
Reflexive Relation: A Relation R on A a set A is said to be Reflexive if xRx for every element of x ? A.
 

The number of reflexive relations on an n-element set is 2n(n-1)
How does this formula work? 
A relation R is reflexive if the matrix diagonal elements are 1. 
 

MATRIX

If we take a closer look the matrix, we can notice that the size of matrix is n2. The n diagonal entries are fixed. For remaining n2 – n entries, we have choice to either fill 0 or 1. So there are total 2n(n-1) ways of filling the matrix.

 Below is the code implementation of the above approach:

CPP




// C++ Program to count reflexive relations
// on a set of first n natural numbers.
#include <iostream>
using namespace std;
 
int countReflexive(int n)
{
   // Return 2^(n*n - n)
   return (1 << (n*n - n));
}
 
int main()
    int n = 3;
    cout << countReflexive(n);
    return 0;
}


Java




// Java Program to count reflexive
// relations on a set of first n
// natural numbers.
 
import java.io.*;
import java.util.*;
 
class GFG {
     
static int countReflexive(int n)
{
 
// Return 2^(n*n - n)
return (1 << (n*n - n));
 
}
 
// Driver function
    public static void main (String[] args) {
    int n = 3;
    System.out.println(countReflexive(n));
         
    }
}
 
// This code is contributed by Gitanjali.


Python3




# Python3 Program to count
# reflexive relations
# on a set of first n
# natural numbers.
 
  
def countReflexive(n):
 
    # Return 2^(n*n - n)
    return (1 << (n*n - n));
 
# driver function
n = 3
ans = countReflexive(n);
print (ans)
 
# This code is contributed by saloni1297


C#




// C# Program to count reflexive
// relations on a set of first n
// natural numbers.
using System;
 
class GFG {
     
    static int countReflexive(int n)
    {
     
        // Return 2^(n*n - n)
        return (1 << (n*n - n));
         
    }
     
    // Driver function
    public static void Main () {
         
    int n = 3;
    Console.WriteLine(countReflexive(n));
    }
}
 
// This code is contributed by vt_m.


PHP




<?php
// PHP Program to count
// reflexive relations on a
// set of first n natural numbers.
 
function countReflexive($n)
{
// Return 2^(n * n - n)
return (1 << ($n * $n - $n));
}
 
//Driver code
$n = 3;
echo countReflexive($n);
 
// This code is contributed by mits
?>


Javascript




<script>
    // Javascript Program to count reflexive
    // relations on a set of first n
    // natural numbers.
     
    function countReflexive(n)
    {
        // Return 2^(n*n - n)
        return (1 << (n*n - n));
    }
     
      let n = 3;
    document.write(countReflexive(n));
     
    // This code is contributed by divyesh072019.
</script>


Output

64

Time Complexity: O(1)
Auxiliary Space: O(1)



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