Output of C programs | Set 48
Last Updated :
05 Sep, 2017
1. What is the output of following program?
#include <stdio.h>
#define square(x) (x * x)
int main()
{
int x, y = 1;
x = square(y + 1);
printf("%d\n", x);
return 0;
}
|
Options:
(A) Error
(B) 4
(C) 3
(D) Garbage value
Answer : (C)
Explanation : The macro function square(x)(x*x) calculates the square of the given number.
Initially int y = 1;
In the next step x = square(y+1);
x = y+1 * y+1; Here square(x) is replaced x*x .
x = 1+1 * 1+1;
x = 1 + 1 + 1;
x = 3;
2. What is the output of following program?
The code given below is executed from command Line.
Input given by the user: myfile 2 4 6
#include <stdio.h>
int main(int argc, char* argv[])
{
int result;
result = argv[2] + argv[4] + argv[6];
printf("%d", result);
return 0;
}
|
Options:
(A) It will reflect a garbage value.
(B) Error
(C) 12
(D) myfile 12
Answer : (B) Error
Explanation : Error because argv[2], argv[4] and argv[6] areof string type and we cannot perform arithmetic operations without converting the string to integer type.
3. What is the output of following program?
#include <stdio.h>
void main()
{
unsigned char x = 400;
printf("%d", x);
}
|
Options:
(A) Error
(B) 144
(C) 400
(D) Garbage value
Answer :(B) 144
Explanation : Since the input is beyond the range of unsigned char it will reflect the input’s cyclic value.
4.What is the output of following program?
#include <stdio.h>
int main()
{
int i;
char input;
for (i = 1; i <= 5; i++) {
scanf("%c", &input);
printf("%c", input);
ungetc(input, stdin);
}
return 0;
}
|
Options:
(A) Error
(B) X
(C) XXXXX
(D) A garbage value.
Answer:(C)- XXXXX
Explanation:The loop will run 5 times. Now, we provide the input as ‘X’. Which is scanned as ‘input’.
printf("%c", input);
The above line prints 'X'
Now the ungetc(input, stdin) statement pushes the character’X’ back into input stream.
For the next run of the loop.
The scanf statement gets the input from “stdin” because of “ungetc” function used previously. Now the printf statement will print ‘X’ Since input= ‘X’ and ungetc(input, stdin) pushes ‘X’ back to the input stream and the same process will take place for the remaining iterations.
5. What is the output of following program?
#include <stdio.h>
int main()
{
printf("Geeksfor ", "Geeks\n");
return 0;
}
|
Options:
(A) Geeksfor
(B) GeeksforGeeks
(C) Error
(D) Geeks
Answer:(A) Geeksfor
Explanation : printf() allows variable number of arguments. Since there is no format specifier, second parameter is ignored with warning.
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