Pi(π) in C++ with Examples
Last Updated :
16 Jun, 2022
In this article, we will discuss some of the mathematical function which is used to derive the value of Pi(Ï€) in C++. Method 1: Using acos() function: Approach:
- The value of Î is calculated using acos() function which returns a numeric value between [-Î , Î ].
- Since using acos(0.0) will return the value for Î /2. Therefore, to get the value of Î :
double pi = 2*acos(0.0);
- Now the value obtained from above equation is estimated as:
printf("%f\n", pi);
Below is the implementation of the above approach:
CPP
#include "bits/stdc++.h"
using namespace std;
void printValueOfPi()
{
double pi = 2 * acos (0.0);
printf ( "%f\n" , pi);
}
int main()
{
printValueOfPi();
return 0;
}
|
Time Complexity: O(1)
Auxiliary Space: O(1)
Method 2: Using asin() function: Approach:
- The value of Î is calculated using asin() function which returns a numeric value between [-Î , Î ].
- Since using asin(1.0) will return the value for Î /2. Therefore, to get the value of Î :
double pi = 2*asin(1.0);
- Now the value obtained from above equation is estimated as:
printf("%f\n", pi);
Below is the implementation of the above approach:
CPP
#include "bits/stdc++.h"
using namespace std;
void printValueOfPi()
{
double pi = 2 * asin (1.0);
printf ( "%f\n" , pi);
}
int main()
{
printValueOfPi();
return 0;
}
|
Time Complexity: O(1)
Auxiliary Space: O(1)
Method 3: Using inbuilt constant value define in the “cmath” library: The value of Pi(Ï€) can directly written using the constant stored in cmath library. The name of the constant is M_PI. Below is the program for printing the value of Pi:
CPP
#include "cmath"
#include "iostream"
using namespace std;
void printValueOfPi()
{
printf ( "%f\n" , M_PI);
}
int main()
{
printValueOfPi();
return 0;
}
|
Time Complexity: O(1)
Auxiliary Space: O(1)
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