Program to find slope of a line
Last Updated :
17 Feb, 2023
Given two coordinates, find the slope of a straight line.
Examples:
Input : x1 = 4, y1 = 2,
x2 = 2, y2 = 5
Output : Slope is -1.5
Approach: To calculate the slope of a line you need only two points from that line, (x1, y1) and (x2, y2). The equation used to calculate the slope from two points is:
Below is the implementation of the above approach:
C++
#include <bits/stdc++.h>
using namespace std;
float slope( float x1, float y1, float x2, float y2)
{
if (x2 - x1 != 0)
return (y2 - y1) / (x2 - x1);
return INT_MAX;
}
int main()
{
float x1 = 4, y1 = 2;
float x2 = 2, y2 = 5;
cout << "Slope is: " << slope(x1, y1, x2, y2);
return 0;
}
|
Java
import java.io.*;
class GFG {
static float slope( float x1, float y1, float x2,
float y2)
{
if (x2 - x1 != 0 )
return (y2 - y1) / (x2 - x1);
return Integer.MAX_VALUE;
}
public static void main(String[] args)
{
float x1 = 4 , y1 = 2 ;
float x2 = 2 , y2 = 5 ;
System.out.println( "Slope is: "
+ slope(x1, y1, x2, y2));
}
}
|
Python
def slope(x1, y1, x2, y2):
if (x2 - x1 ! = 0 ):
return ( float )(y2 - y1) / (x2 - x1)
return sys.maxint
x1 = 4
y1 = 2
x2 = 2
y2 = 5
print "Slope is:" , slope(x1, y1, x2, y2)
|
C#
using System;
public static class GFG {
public static float slope( float x1, float y1, float x2,
float y2)
{
if (x2 - x1 != 0F) {
return (y2 - y1) / (x2 - x1);
}
return int .MaxValue;
}
internal static void Main()
{
float x1 = 4F;
float y1 = 2F;
float x2 = 2F;
float y2 = 5F;
Console.Write( "Slope is: " );
Console.Write(slope(x1, y1, x2, y2));
}
}
|
PHP
<?php
function slope( $x1 , $y1 , $x2 , $y2 )
{
if ( $x1 == $x2 )
{
return PHP_INT_MAX;
}
return ( $y2 - $y1 ) /
( $x2 - $x1 );
}
$x1 = 4;
$y1 = 2;
$x2 = 2;
$y2 = 5;
echo "Slope is: "
, slope( $x1 , $y1 ,
$x2 , $y2 );
?>
|
Javascript
function slope(x1, y1, x2, y2)
{
if (x2 - x1 != 0)
{
return (y2 - y1) / (x2 - x1);
}
return Number.MAX_VALUE;
}
var x1 = 4;
var y1 = 2;
var x2 = 2;
var y2 = 5;
console.log( "Slope is: " + slope(x1, y1, x2, y2));
|
Time Complexity: O(1)
Auxiliary Space: O(1)
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