Program to convert Java list of Shorts to an Indexed Sequence in Scala

Last Updated : 14 Jan, 2020

A java list of Shorts can be converted to an Indexed Sequence in Scala by utilizing toIndexedSeq method of Java in Scala. Here, we need to import Scala’s JavaConversions object in order to make this conversions work else an error will occur.
Now, lets see some examples and then discuss how it works in details.
Example:1#

// Scala program to convert Java list  
// to an Indexed Sequence in Scala 
  
// Importing Scala's JavaConversions object 
import scala.collection.JavaConversions._
  
  
// Creating object 
object GfG 
{  
  
    // Main method 
    def main(args:Array[String]) 
    { 
      
        // Creating list of Shorts in Java 
        val list = new java.util.ArrayList[Short]() 
          
        // Adding Shorts to the list 
        list.add(100) 
        list.add(1000) 
        list.add(301) 
          
        // Converting list to an Indexed Sequence  
        val ind = list.toIndexedSeq 
          
        // Displays Indexed Sequence 
        println(ind) 
      
    } 
} 

Output:

Vector(100, 1000, 301)

Example:2#

// Scala program to convert Java list  
// to an Indexed Sequence in Scala 
  
// Importing Scala's JavaConversions object 
import scala.collection.JavaConversions._
  
  
// Creating object 
object GfG 
{  
  
    // Main method 
    def main(args:Array[String]) 
    { 
      
        // Creating list of Shorts in Java 
        val list = new java.util.ArrayList[Short]() 
          
        // Adding Shorts to the list 
        list.add(-111) 
        list.add(-1000) 
        list.add(-123) 
          
        // Converting list to an Indexed Sequence  
        val ind = list.toIndexedSeq 
          
        // Displays Indexed Sequence 
        println(ind) 
      
    } 
} 