Program to convert Java list to Seq in Scala
A java list can be converted to sequence in Scala by utilizing toSeq method of Java in Scala. Here, you need to import Scala’s JavaConversions object in order to make this conversions work else an error will occur.
Now, lets see some examples and then discuss how it works in details.
Example:1#
import scala.collection.JavaConversions. _
object GfG
{
def main(args : Array[String])
{
val list = new java.util.ArrayList[Int]()
list.add( 5 )
list.add( 6 )
val seq = list.toSeq
println(seq)
}
}
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Therefore, a sequence of integer is returned. Here, firstly a list is created where, the int elements are added to it utilizing add method. After that toSeq method is utilized in order to convert the stated list to a sequence.
Example:2#
import scala.collection.JavaConversions. _
object GfG
{
def main(args : Array[String])
{
val list = new java.util.ArrayList[Int]()
list.add( 5 )
list.add( 6 )
list.add( 1 )
val seq = list.toSeq
println(seq)
}
}
|
It is same as above example but here one more element is added in the stated list and then its returned here in the form of sequence.
Last Updated :
29 Nov, 2019
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