Python Program For Reversing A Linked List In Groups Of Given Size – Set 1
Given a linked list, write a function to reverse every k nodes (where k is an input to the function).Â
Example:Â
Input: 1->2->3->4->5->6->7->8->NULL, K = 3Â
Output: 3->2->1->6->5->4->8->7->NULLÂ
Input: 1->2->3->4->5->6->7->8->NULL, K = 5Â
Output: 5->4->3->2->1->8->7->6->NULLÂ
Algorithm: reverse(head, k)Â
- Reverse the first sub-list of size k. While reversing keep track of the next node and previous node. Let the pointer to the next node be next and pointer to the previous node be prev. See this post for reversing a linked list.
- head->next = reverse(next, k) ( Recursively call for rest of the list and link the two sub-lists )
- Return prev ( prev becomes the new head of the list (see the diagrams of an iterative method of this post )
Below is image shows how the reverse function works:Â
Below is the implementation of the above approach:
Python
class Node:
def __init__( self , data):
self .data = data
self . next = None
class LinkedList:
def __init__( self ):
self .head = None
def reverse( self , head, k):
if head = = None :
return None
current = head
next = None
prev = None
count = 0
while (current is not None and
count < k):
next = current. next
current. next = prev
prev = current
current = next
count + = 1
if next is not None :
head. next = self .reverse( next , k)
return prev
def push( self , new_data):
new_node = Node(new_data)
new_node. next = self .head
self .head = new_node
def printList( self ):
temp = self .head
while (temp):
print temp.data,
temp = temp. next
llist = LinkedList()
llist.push( 9 )
llist.push( 8 )
llist.push( 7 )
llist.push( 6 )
llist.push( 5 )
llist.push( 4 )
llist.push( 3 )
llist.push( 2 )
llist.push( 1 )
print "Given linked list"
llist.printList()
llist.head = llist.reverse(llist.head, 3 )
print "Reversed Linked list"
llist.printList()
|
Output:Â
Given Linked List
1 2 3 4 5 6 7 8 9
Reversed list
3 2 1 6 5 4 9 8 7
Complexity Analysis:Â
- Time Complexity: O(n).Â
Traversal of list is done only once and it has ‘n’ elements.
- Auxiliary Space: O(n/k).Â
For each Linked List of size n, n/k or (n/k)+1 calls will be made during the recursion.
Please refer complete article on Reverse a Linked List in groups of given size | Set 1 for more details!
Last Updated :
18 May, 2022
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