Python Program to Find the Gcd of Two Numbers
Last Updated :
22 Jun, 2023
Given two numbers, The task is to find the GCD of the two numbers.
Python Program to Find the Gcd of Two Numbers Using STL
In Python, the math module contains a number of mathematical operations, which can be performed with ease using the module. math.gcd() function compute the greatest common divisor of 2 numbers mentioned in its arguments.
Syntax: math.gcd(x, y)
Parameter:
x : Non-negative integer whose gcd has to be computed.
y : Non-negative integer whose gcd has to be computed.
Returns: An absolute/positive integer value after calculating the GCD of given parameters x and y. Exceptions: When Both x and y are 0, function returns 0, If any number is a character, Type error is raised.
Python3
import math
print("The gcd of 60 and 48 is : ", end="")
print(math.gcd(60, 48))
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Output
The gcd of 60 and 48 is : 12
Time complexity: O(log(min(a,b))), as it uses the Euclidean Algorithm for finding the GCD.
Auxiliary Space: O(log(n)), as it uses recursion and the maximum depth of recursion is log(n).
Python Program to Find the Gcd of Two Numbers Using Recursion
This code calculates the greatest common divisor (gcd) of two numbers using a recursive algorithm. It uses the Euclidean algorithm to find the gcd and returns the result.
Python3
def hcf(a, b):
if(b == 0):
return a
else:
return hcf(b, a % b)
a = 60
b = 48
print("The gcd of 60 and 48 is : ", end="")
print(hcf(60, 48))
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Output
The gcd of 60 and 48 is : 12
Time complexity: O(log(min(a,b))), as it uses the Euclidean Algorithm for finding the GCD.
Auxiliary Space: O(log(n)), as it uses recursion and the maximum depth of recursion is log(n).
Find the Gcd of Two Numbers Using Euclidean Algorithm
The Euclid’s algorithm (or Euclidean Algorithm) is a method for efficiently finding the greatest common divisor (GCD) of two numbers. The GCD of two integers X and Y is the largest number that divides both of X and Y (without leaving a remainder).
Pseudo Code of the Algorithm-
- Let a, b be the two numbers
- a mod b = R
- Let a = b and b = R
- Repeat Steps 2 and 3 until a mod b is greater than 0
- GCD = b
- Finish
Python3
def gcd(a, b):
if (a == 0):
return b
if (b == 0):
return a
if (a == b):
return a
if (a > b):
return gcd(a-b, b)
return gcd(a, b-a)
a = 98
b = 56
if(gcd(a, b)):
print('GCD of', a, 'and', b, 'is', gcd(a, b))
else:
print('not found')
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Output
GCD of 98 and 56 is 14
Time complexity: O(log(min(a,b))), as it uses the Euclidean algorithm which has a time complexity of O(log(min(a,b))).
Auxiliary Space: O(1), as it only uses a few variables and does not require any additional data structures.
Find GCD with Lambda function
In this code, the lambda function gcd takes two arguments a and b. It uses the same recursive algorithm as the previous code example to calculate the gcd. The function returns a if b is equal to 0, otherwise it calls itself with b and a % b. Finally, the gcd is printed using the lambda function.
Python3
gcd = lambda a, b: a if b == 0 else gcd(b, a % b)
a = 60
b = 48
print("The gcd of 60 and 48 is:", gcd(a, b))
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Output:
The gcd of 60 and 48 is: 12
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