Python3 Program to Modify a matrix by rotating ith row exactly i times in clockwise direction
Last Updated :
30 May, 2022
Given a matrix mat[][] of dimensions M * N, the task is to print the matrix obtained after rotating every ith row of the matrix i times in a clockwise direction.
Examples:
Input: mat[][] = {{1, 2, 3}, {4, 5, 6}, {7, 8, 9}}
Output:
1 2 3
6 4 5
8 9 7
Explanation:
The 0th row is rotated 0 times. Therefore, the 0th row remains the same as {1, 2, 3}.
The 1st row is rotated 1 times. Therefore, the 1st row modifies to {6, 4, 5}.
The 2nd row is rotated 2 times. Therefore, the 2nd row modifies to {8, 9, 7}.
After completing the above operations, the given matrix modifies to {{1, 2, 3}, {6, 4, 5}, {8, 9, 7}}.
Input: mat[][] = {{1, 2, 3, 4}, {4, 5, 6, 7}, {7, 8, 9, 8}, {7, 8, 9, 8}}
Output:
1 2 3 4
7 4 5 6
9 8 7 8
8 9 8 7
Approach: Follow the steps below to solve the problem:
Below is the implementation of the above approach:
Python3
def rotateMatrix(mat):
i = 0
mat1 = []
for it in mat:
it.reverse()
it1 = it[:i]
it1.reverse()
it2 = it[i:]
it2.reverse()
i += 1
mat1.append(it1 + it2)
for rows in mat1:
for cols in rows:
print(cols, end = " ")
print()
if __name__ == "__main__":
mat = [ [ 1, 2, 3 ], [ 4, 5, 6 ], [ 7, 8, 9 ] ]
rotateMatrix(mat)
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Output:
1 2 3
6 4 5
8 9 7
Time Complexity: O(N*M), as we are using nested loops to traverse N*M times.
Auxiliary Space: O(1), as we are not using any extra space.
Please refer complete article on Modify a matrix by rotating ith row exactly i times in clockwise direction for more details!
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