If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:
(A) 4 days
(B) 5 days
(C) 6 days
(D) 7 days
Answer: (A)
Explanation: Let the amount of work 1 man can do in 1 day be x and the amount of work 1 boys can do in 1 day be y.
Then, 6x + 8y = 1/10 and 26x + 48y = ½.
Solving these two equations, we get: x = 1/100 and y = 1/200.
Amount of work done by 15 men and 20 boys in 1 day = 15/100 + 20/200 = ¼.
Therefore, the answer is 4 days.
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