Find the Probability of getting 53 Sundays in a Non-Leap Year?

Find the Probability of getting 53 Sundays in a Non-Leap Year.

Answer: The probability of getting 53 Sundays in a non-leap year is 1/7 or approximately 0.1429.

To find the probability of getting 53 Sundays in a non-leap year, we divide the number of non-leap years with 53 Sundays by the total number of non-leap years. Since each year has 52 weeks and 1 day, for 53 Sundays to occur, the year must start on a Sunday. In a non-leap year, this happens once every 7 years. So, the probability is 1/7.

Probability = Number of favourable outcomes / Total number of events

Here, Number of favorable outcomes = 1

And, Total number of events = 7

So, Probability = 1/7

Thus, the probability of getting 53 Sundays in a non-leap year is 1/7.

Conclusion

In conclusion, the probability of encountering 53 Sundays in a non-leap year is 1/7 or approximately 0.1429. This calculation is derived from the fact that a non-leap year starting on a Sunday occurs once every 7 years. By understanding this probability, we gain insights into the cyclical nature of calendar years and their alignment with the days of the week.

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