Golang | Creating a string that contains regexp metacharacters
Last Updated :
05 Sep, 2019
A regular expression is a sequence of characters which define a search pattern. Go language support regular expressions. A regular expression is used for parsing, filtering, validating, and extracting meaningful information from large text, like logs, the output generated from other programs, etc.
In Go regexp, you are allowed to create a string that escapes all regular expression metacharacters in the specified text with the help of QuoteMeta() function. The returned string of this function is a regular expression matching the literal text. This function is defined under the regexp package, so for accessing this method you need to import the regexp package in your program.
Syntax:
func QuoteMeta(str string) string
Example 1:
package main
import (
"fmt"
"regexp"
)
func main() {
res1 := regexp.QuoteMeta(`String 1: .+*()|[]{}^$`)
fmt.Println(res1)
res2 := regexp.QuoteMeta(`String 2: +()*`)
fmt.Println(res2)
res3 := regexp.QuoteMeta(`String 3: []|{}$`)
fmt.Println(res3)
res4 := regexp.QuoteMeta(`String 4: ^$*-,`)
fmt.Println(res4)
}
|
Output:
String 1: \.\+\*\(\)\|\[\]\{\}\^\$
String 2: \+\(\)\*
String 3: \[\]\|\{\}\$
String 4: \^\$\*-,
Example 2:
package main
import (
"fmt"
"regexp"
)
func main() {
s1 := `+*?()|[]^$`
s2 := `+*?()|[]^$
`
if s1 == s2 {
res := regexp.QuoteMeta(s1)
fmt.Println( "String:" , res)
} else {
fmt.Println( "Not Equal" )
}
}
|
Output:
Not Equal
Share your thoughts in the comments
Please Login to comment...