Integer highestOneBit() Method in Java
Last Updated :
13 Dec, 2021
The Integer.highestOneBit() method of java.lang returns an integer value with at most a single one-bit which is in the position of the highest-order (ie.leftmost) one-bit for the given int value. If the specified value has no one-bits in its two’s complement binary representation then it returns zero, simply if it is equal to zero.
Syntax:
public static int highestOneBit(int a)
Parameters: The method takes one parameter a of integer type that refers to the value whose highest order bit is to be returned or on which the operation is to be performed.
Returns : The method can return two types of values:
- Returns an integer value with a single 1-bit, in the position of the highest-order one-bit in the specified value
- Returns zero if the specified value is equal to zero.
Examples:
Input: 19
Output: Highest one bit of the given integer is = 16
Input: -9
Output: Highest one bit of the given integer is = -2147483648
Explanation:
Consider any integer a = 19
Binary Representation = 0001 0011
Highest bit(at 4) i.e.0001 0000
so result = 2^4=16
Below programs illustrate the Java.lang.Integer.highestOneBit() Method.
Program 1: For a positive number.
java
import java.lang.*;
public class HighestOneBit {
public static void main(String[] args)
{
int a = 29 ;
System.out.println("Number is = " + a);
System.out.print("Highest one bit of the given integer is = ");
System.out.println(Integer.highestOneBit(a));
a = 44 ;
System.out.println("Number is = " + a);
System.out.print("Highest one bit of the given integer is = ");
System.out.println(Integer.highestOneBit(a));
}
}
|
Output:
Number is = 29
Highest one bit of the given integer is = 16
Number is = 44
Highest one bit of the given integer is = 32
Program 2: For a negative number.
java
import java.lang.*;
public class HighestOneBit {
public static void main(String[] args)
{
int a = - 9 ;
System.out.println("Number is = " + a);
System.out.print("Highest one bit of the given integer is = ");
System.out.println(Integer.highestOneBit(a));
}
}
|
Output:
Number is = -9
Highest one bit of the given integer is = -2147483648
Program 3: For a decimal value.
Note:It returns an error message when a decimal value is passed as an argument because of incompatible types.
java
import java.lang.*;
public class HighestOneBit {
public static void main(String[] args)
{
int a = 84.22 ;
System.out.println("Number is = " + a);
System.out.print("Highest one bit of the given integer is = ");
System.out.println(Integer.highestOneBit(a));
}
}
|
Output:
prog.java:9: error: incompatible types: possible lossy conversion from double to int
int a = 84.22;
^
1 error
Program 4: For a String.
Note:It returns an error message when a String is passed as an argument because of incompatible types.
java
import java.lang.*;
public class HighestOneBit {
public static void main(String[] args)
{
int a = " 34 ";
System.out.println("Number is = " + a);
System.out.print("Highest one bit of the given integer is = ");
System.out.println(Integer.highestOneBit(a));
}
}
|
Output:
prog.java:9: error: incompatible types: String cannot be converted to int
int a = "34";
^
1 error
Share your thoughts in the comments
Please Login to comment...