Java Integer compare() method
Last Updated :
05 Dec, 2018
The compare() method of Integer class of java.lang package compares two integer values (x, y) given
as a parameter and returns the value zero if (x==y), if (x < y) then it returns a value less than zero and
if (x > y) then it returns a value greater than zero.
Syntax :
public static int compare(int x, int y)
Parameter :
x : the first int to compare
y : the second int to compare
Return :
This method returns the value zero if (x==y),
if (x < y) then it returns a value less than zero
and if (x > y) then it returns a value greater than zero.
Example :To show working of java.lang.Integer.compare() method.
import java.lang.Integer;
class Gfg {
public static void main(String args[])
{
int a = 10 ;
int b = 20 ;
System.out.println(Integer.compare(a, b));
int x = 30 ;
int y = 30 ;
System.out.println(Integer.compare(x, y));
int w = 15 ;
int z = 8 ;
System.out.println(Integer.compare(w, z));
}
}
|
Output:
-1
0
1
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