Java Program to Sort ArrayList of Custom Objects By Property
Last Updated :
17 Nov, 2020
Here we are going to look at the approach of sorting an ArrayList of custom objects by using a property.
Approach:
1. Create a getter function which returns the value stored in the class variable.
2. Create a list and use sort() function which takes the values of the list as arguments and compares them with compareTo() method.
3. This function will then return a positive number if the first argument’s property is greater than the second’s, negative if it is less and zero if they are equal.
Implementation
Java
import java.util.*;
public class Main {
private String value;
public Main(String val) { this .value = val; }
public String getValue() { return this .value; }
static ArrayList<Main> list = new ArrayList<>();
public static void sortList( int length)
{
list.sort(
(a, b) -> a.getValue().compareTo(b.getValue()));
System.out.println( "Sorted List : " );
for (Main obj : list) {
System.out.println(obj.getValue());
}
}
public static void main(String[] args)
{
Scanner sc = new Scanner(System.in);
System.out.print(
"How many characters you want to enter : " );
int l = sc.nextInt();
for ( int i = 0 ; i < l; i++) {
list.add( new Main(sc.next()));
}
sortList();
}
}
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Output
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