Javascript Program to Generate a matrix having sum of secondary diagonal equal to a perfect square
Last Updated :
01 Feb, 2022
Given an integer N, the task is to generate a matrix of dimensions N x N using positive integers from the range [1, N] such that the sum of the secondary diagonal is a perfect square.
Examples:
Input: N = 3
Output:
1 2 3
2 3 1
3 2 1
Explanation:
The sum of secondary diagonal = 3 + 3 + 3 = 9(= 32).
Input: N = 7
Output:
1 2 3 4 5 6 7
2 3 4 5 6 7 1
3 4 5 6 7 1 2
4 5 6 7 1 2 3
5 6 7 1 2 3 4
6 7 1 2 3 4 5
7 1 2 3 4 5 6
Explanation:
The sum of secondary diagonal = 7 + 7 + 7 + 7 + 7 + 7 + 7 = 49(= 72).
Approach: Since the generated matrix needs to be of dimensions N x N, therefore, to make the sum of elements in the secondary diagonal a perfect square, the idea is to assign N at each index of the secondary diagonal. Therefore, the sum of all N elements in this diagonal is N2, which is a perfect square. Follow the steps below to solve the problem:
- Initialize a matrix mat[][] of dimension N x N.
- Initialize the first row of the matrix as {1 2 3 … N}.
- Now for the remaining rows of the matrix, fill each row by circular left shift of the arrangement of the previous row of the matrix by 1.
- Print the matrix after completing the above steps.
Below is the implementation of the above approach:
Javascript
<script>
function diagonalSumPerfectSquare( arr,N)
{
for (let i = 0; i < N; i++)
{
for (let j = 0; j < N; j++)
{
document.write(arr[(j + i) % 7] + " " );
}
document.write( "<br/>" );
}
}
let N = 7;
let arr = new Array(N).fill(0);
for (let i = 0; i < N; i++)
{
arr[i] = i + 1;
}
diagonalSumPerfectSquare(arr, N);
</script>
|
Output
1 2 3 4 5 6 7
2 3 4 5 6 7 1
3 4 5 6 7 1 2
4 5 6 7 1 2 3
5 6 7 1 2 3 4
6 7 1 2 3 4 5
7 1 2 3 4 5 6
Time Complexity: O(N2)
Auxiliary Space: O(N)
Please refer complete article on Generate a matrix having sum of secondary diagonal equal to a perfect square for more details!
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