NCERT Solutions Class 9 – Chapter 1 Number System – Exercise 1.5 Last Updated : 25 Apr, 2024 Improve Improve Like Article Like Save Share Report Question 1. Find the Value of: (i) 641/2 641/2 = (8 × 8)1/2 = (82)½ = 81 = 8 (ii) 321/5 321/5 = (2 x 2 x 2 x 2 x 2)1/5 = (25)⅕ = 21 = 2 (iii) 1251/3 (125)1/3 = (5 × 5 × 5)1/3 = (53)⅓ = 51 = 5 Question 2. Find the value of: (i) 93/2 93/2 = (3 × 3)3/2 = (32)3/2 = 33 = 27 (ii) 322/5 322/5 = (2 × 2 × 2 × 2 × 2)2/5 = (25)2⁄5 = 22 = 4 (iii) 163/4 163/4 = (2 × 2 × 2 × 2)3/4 = (24)3⁄4 = 23 = 8 (iv) 125-1/3 125-1/3 = (5 × 5 × 5)-1/3 = (53)-1⁄3 = 5-1 = 1/5 Question 3. Simplify the followings: (i) 22/3 × 21/5 22/3 × 21/5 = 2(2/3) + (1/5) ⸪ As, am × an = am + n = 213/15 (ii) (1/33)7 (1/33)7 = (3-3)7 ⸪ As, (am)n = am x n = 3-21 (iii) 111/2/111/4 111/2/111/4 = 11(1/2) – (1/4) ⸪ As, am × a-n = am – n = 111/4 (iv) 71/2 × 81/2 71/2 × 81/2 = (7 × 8)1/2 ⸪ As, am × bm = (a × b)m = 561/2 Like Article Suggest improvement Previous Class 11 NCERT Solutions - Chapter 1 Sets - Exercise 1.6 Next Chapter 4: International Context| Class 12 Political Science Share your thoughts in the comments Add Your Comment Please Login to comment...