PYGLET – Getting Window Visible Status
Last Updated :
06 Oct, 2022
In this article we will see how we can get the window visible status in PYGLET module in python. Pyglet is easy to use but powerful library for developing visually rich GUI applications like games, multimedia etc. A window is a “heavyweight” object occupying operating system resources. Windows may appear as floating regions or can be set to fill an entire screen (fullscreen).The window visible status is True is it is visible else it is False We can create a window with the help of command given below
pyglet.window.Window(width, height, title)
In order to create window we use visible attribute with the window object Syntax : window.visible Argument : It takes no argument Return : It returns bool
Below is the implementation
Python3
import pyglet
import pyglet.window.key
width = 500
height = 500
title = "Geeksforgeeks"
window = pyglet.window.Window(width, height, title)
text = "GeeksforGeeks"
label = pyglet.text.Label(text,
font_name = 'Times New Roman' ,
font_size = 36 ,
x = window.width / / 2 , y = window.height / / 2 ,
anchor_x = 'center' , anchor_y = 'center' )
new_label = pyglet.text.Label(text,
font_name = 'Times New Roman' ,
font_size = 10 ,
x = 25 , y = 25 )
@window .event
def on_draw():
window.clear()
label.draw()
@window .event
def on_key_press(symbol, modifier):
if symbol = = pyglet.window.key.C:
window.close()
img = image = pyglet.resource.image("logo.png")
window.set_icon(img)
value = window.visible
print ("Window Visible Status : ")
print (value)
pyglet.app.run()
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Output :
Window Visible Status :
True
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