Python Program to Print matrix in snake pattern
Last Updated :
31 Jul, 2023
Given an n x n matrix .In the given matrix, you have to print the elements of the matrix in the snake pattern.
Examples:
Input :mat[][] = { {10, 20, 30, 40},
{15, 25, 35, 45},
{27, 29, 37, 48},
{32, 33, 39, 50}};
Output : 10 20 30 40 45 35 25 15 27 29
37 48 50 39 33 32
Input :mat[][] = { {1, 2, 3},
{4, 5, 6},
{7, 8, 9}};
Output : 1 2 3 6 5 4 7 8 9
Python Program to Print matrix in snake pattern
We traverse all rows. For every row, we check if it is even or odd. If even, we print from left to right else print from right to left.
Python3
M = 4
N = 4
def printf(mat):
global M, N
for i in range (M):
if i % 2 = = 0 :
for j in range (N):
print ( str (mat[i][j]),
end = " " )
else :
for j in range (N - 1 , - 1 , - 1 ):
print ( str (mat[i][j]),
end = " " )
mat = [[ 10 , 20 , 30 , 40 ],
[ 15 , 25 , 35 , 45 ],
[ 27 , 29 , 37 , 48 ],
[ 32 , 33 , 39 , 50 ]]
printf(mat)
|
Output
10 20 30 40 45 35 25 15 27 29 37 48 50 39 33 32
Time complexity: O(n^m) ,Traversing over all the elements of the matrix, therefore N X M elements are there.
Auxiliary space : O(1)
Reversing Alternate rows Using Slicing
Python3
M = 4
N = 4
def printf(mat):
global M, N
for i in range (M):
if i % 2 ! = 0 :
mat[i] = mat[i][:: - 1 ]
for i in range (M):
for j in range (N):
print (mat[i][j], end = ' ' )
mat = [[ 10 , 20 , 30 , 40 ],
[ 15 , 25 , 35 , 45 ],
[ 27 , 29 , 37 , 48 ],
[ 32 , 33 , 39 , 50 ]]
printf(mat)
|
Output
10 20 30 40 45 35 25 15 27 29 37 48 50 39 33 32
Time Complexity: O(N x M), Traversing over all the elements of the matrix, therefore N X M elements are there.
Auxiliary Space: O(1)
Please refer complete article on Print matrix in snake pattern for more details!
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