Python | Sympy encloses_point() method Last Updated : 30 Jan, 2020 Improve Improve Like Article Like Save Share Report In sympy, the function encloses_point() is used to check whether the given point is encolsed by given ellipse or not. Syntax: Ellipse.encloses_point(point) Return: True:if point is enclosed by ellipse, otherwise False. Example #1: # import sympy and geometry module from sympy import * from sympy.geometry import * x = Point(0, 0) # making ellipse with given point as center and radii e1 = Ellipse(x, 3, 2) # using encloses_point() method isEnclosed = e1.encloses_point((0, 0)) print(isEnclosed) Output: True Example #2: # import sympy and geometry module from sympy import * from sympy.geometry import * x = Point(3, 1) # making ellipse with given point as center, hradius and eccentricity e2 = Ellipse(x, hradius = 3, eccentricity = Rational(4, 5)) # using encloses_point() method isEnclosed = e2.encloses_point((4, 6)) print(isEnclosed) Output: False Like Article Suggest improvement Next Python – Sympy Polygon.encloses_point() method Share your thoughts in the comments Add Your Comment Please Login to comment...