Scala Queue intersect() method with example
Last Updated :
29 Oct, 2019
The intersect() method is utilized to return a new queue that consists of elements that are present in both the given queues.
Method Definition: def intersect[B >: A](that: collection.Seq[B]): Queue[A]
Return Type: It returns a new queue that consists of elements that are present in both the given queues.
Example #1:
import scala.collection.mutable. _
object GfG
{
def main(args : Array[String])
{
val q 1 = Queue( 1 , 3 , 2 , 7 , 6 , 5 )
val q 2 = Queue( 1 , 13 , 2 , 17 , 6 , 15 )
println( "Queue_1: " + q 1 )
println( "Queue_2: " + q 2 )
val result = q 1 .intersect(q 2 )
print( "The elements in both the queues: " )
result.foreach(x => print(x + " " ))
}
}
|
Output:
Queue_1: Queue(1, 3, 2, 7, 6, 5)
Queue_2: Queue(1, 13, 2, 17, 6, 15)
The elements in both the queues: 1 2 6
Example #2:
import scala.collection.mutable. _
object GfG
{
def main(args : Array[String])
{
val q 1 = Queue( 1 , 3 , 2 , 7 , 6 , 5 )
val q 2 = Queue( 11 , 3 , 12 , 7 , 16 , 5 )
println( "Queue_1: " + q 1 )
println( "Queue_2: " + q 2 )
val result = q 1 .intersect(q 2 )
print( "The elements in both the queues: " + result)
}
}
|
Output:
Queue_1: Queue(1, 3, 2, 7, 6, 5)
Queue_2: Queue(11, 3, 12, 7, 16, 5)
The elements in both the queues: Queue(3, 7, 5)
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